In the first attempt, Opus 4.7 successfully completed it and proved it. However, the solution is to enumerate all possible space and .filter out anything that doesn't qualify my definition, which is obviously not ideal (if cheating is too harsh).

@_torayuri3 notes8 replies0 tags, 1 user following1 followeri create thingsenter to follow7d · 2 repliesenter to reply

OK. I've translated the (correctness) requirements of LeetCode No.22 to Lean, and ask Claude Code to both implement a solution and prove it.