I wanna learn how to use source film maker...
Any conversation
็ๆฅๅฏไปฅๅไธญๆใๅ ไธบๆฒกๆ่บซไปฝ่ฏ๏ผๆไปฅไธ่ฝๆฅๆๆๆบๅท๏ผๆฅ็ไธ่ฝๆณจๅ็จณๅฎ็email๏ผไนๅฐฑๆฒกๆณๆณจๅๅ
ๅฎนๅนณๅฐ๏ผๅๅธๅ
ๅฎนใhotmailๅ ไธบๆๆฒกๆ็จณๅฎ็ipๅฐๅ๏ผๅธธๅธธๅฐ็ฆๆ็email่ดฆๅท๏ผๆ็mastodon่ดฆๅทๅ ๆญคไนๆฒกๆณ้ฟๆไฝฟ็จใๆๅธๆ่ฟๆฏไธไธชๆๅฏไปฅ้ฟๆๅๅธๅ
ๅฎน็ๅฐๆน
It seems I can post in Chinese. Because I don't have an ID card, I can't have a phone number, and therefore can't register a stable email address, which means I can't register on content platforms or publish content. Hotmail frequently blocks my email account because I don't have a stable IP address, so my Mastodon account can't be used long-term. I hope this is a place where I can publish content consistently.
let i=0;while(++i){process.stdout.write(i%80==0?'\n':Math.random()<0.5?'/':'\\')}\\\//\/\\\\\\\///\///\\\\\//\///\/\/\\//\/\//\//\/\//\\/\///\\\\\\//\\\\\/\\\\/
\\/\\/\/\///\\\/\///\/\/////\\///\/\\/\\\//\\\/\///////\\\/\////\\\/\\\//\\/\//
\\//\\\\\/\\\/\///\\///\\//\\\\/\//\\\//\////\//\\\\////\\/\/\/////\//\\\//\///
\\/\/\\//\\///\/\\\//\/\/\\\///\/\\\/\\/\\\\/\\\\\\\\\\/\\//\/\\/\///\//\\\//\\
/\/\\\\/\/\\/\\/\\/\\\\\\/\\\/\\//////\/\//\\\//\//\//\\/\\\/\//\\\//\\\\\\\/\/
\\\///\////////\\/////\\//\/\///\\\\\////\/\\\\/\//\\/\/////\\\//\\/\/\\\\\////
\///\/\/////\//\////\\\/\\/////\\\////\//\\\\/\\\\//\\\///\\\\\\//\\////\//////
/\/////\\\\\\//\\/\/\///\////\/\\\///\\///\//\/\/\\\/\\/\\\\\\//\/\\\///\\/\/\\
/\\///\/\\\/\\\\//\/\///\\\\\/\/\//\\/\\/\/\///\/\//\/\///\\\///\//\/\///\\\\/\
\\\\/\\\\/\/\\\\\///\/\////\\///\\///\\/\/\\\\\/////\\\\\//\\\\/\\\\\\///\\///\
\\/\//\\//\///\/\///\\\\/\//\/\\/\/\//\\/\/\/\\/\/\\/\\\\/\/////\\\///\\\\\//\\A thing I've been doing lately is trying to come to the same conclusions others have without looking their the direct techniques and code. Last night I tried to figure out why people do vector based retrieval for RAG and ended up running these experiments: n0tls.com/โฆ/2026-09-03-i-think-โฆrag-with-grep.html
I'm still going to do an explore agent.
mandelbrot
for y in range(10):
s=''
for x in range(25):
a=[]
for q in range(2):
z=c=x/25*3-2+1j*((y*2+q)/10-1);n=40
while n and abs(z)<2:z=z*z+c;n-=1
a+=[n<5]
s+=" โโโ"[a[0]+2*a[1]]
print(s)
โโ
โโโโโโโโ
โ โโโโโโโโโ
โโโโโโโโโโโโโ
โโโโโโโโโโโโโโโโโโโ
โโโ โโโโโโโโโ
โโโโโโโโ
โ โโโโ
โโ

