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wrote:

prussia's emoticon is so cute! (=ヮ≖)

wrote:

Vagyis attól még, hogy trehány vagyok, még működhetne jobban is az anyagmegmaradás törvénye, mint éppen errefelé, vagyis errefelé pláne működnie kellene, mégsem ezt teszi.

So even though I'm clumsy, the law of conservation of matter could still work better than it does here, or rather, it shouldn't work here, but it doesn't.

wrote:

🐉 show code

let N=6,D0=[0,1,0,-1],D1=[1,0,-1,0],s=[],g={},d=x=y=xa=xb=ya=yb=0;
for(let n=0;n<N;n++){s=s.concat([1]).concat(s.map(x=>!x).reverse())}
for(let i=0;i<s.length;i++) {
  x<xa && (xa=x);y<ya && (ya=y);x>xb && (xb=x);y>yb && (yb=y);
  let t=s[i]?1:-1,e=(d+t+4)%4;
  g[x]||(g[x]={});
  g[x][y]=g[x][y]?"┼":"┌┐└┘"[(t*(D0[d]+D0[e])>0?0:2)+(t*(D1[d]+D1[e])>0?0:1)];
  x+=D0[e];y+=D1[e];d=e;
}
for(j=yb;j>=ya;j--) {
  let u=""; for(i=xa;i<=xb;i++){u+=(g[i][j]||"·")} console.log(u);
}

·┌┐┌┐·······
┌┘└┼┘····┌┐·
└··└┐┌┐···└┐
···┌┼┼┘···┌┘
···└┼┼┐┌┐┌┼┐
···┌┼┘└┼┼┘└┘
···└┼┐·└┼┐··
····└┘··└┘··

continued:

OK, so you only get 10 lines of output. (I tried to get ChatGPT to write this program but it kept messing up, so I wrote it by hand.)

wrote:

OK. I've translated the (correctness) requirements of LeetCode No.22 to Lean, and ask Claude Code to both implement a solution and prove it.

continued:

In the first attempt, Opus 4.7 successfully completed it and proved it. However, the solution is to enumerate all possible space and .filter out anything that doesn't qualify my definition, which is obviously not ideal (if cheating is too harsh).

continued:

I can't think of a good way to also prevent that kind of solutions and ended up prompting "please don't enumerate and filter". Opus 4.7 then reimplemented and proved the backtracking algorithm.

wrote:

Zik is my pet project - a photos manager that is as fast as possible and as small as possible. It leaves sparks as it goes (lol jk)

……

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