wrote:
I love the "feel" of this place. It's minimal, but not too minimal. Nice work! I'm probably gonna be a little chatty on here. If anyone minds that, then just @ me :-)
let i=0;while(++i){process.stdout.write(i%80==0?'\n':Math.random()<0.5?'/':'\\')}\\\//\/\\\\\\\///\///\\\\\//\///\/\/\\//\/\//\//\/\//\\/\///\\\\\\//\\\\\/\\\\/
\\/\\/\/\///\\\/\///\/\/////\\///\/\\/\\\//\\\/\///////\\\/\////\\\/\\\//\\/\//
\\//\\\\\/\\\/\///\\///\\//\\\\/\//\\\//\////\//\\\\////\\/\/\/////\//\\\//\///
\\/\/\\//\\///\/\\\//\/\/\\\///\/\\\/\\/\\\\/\\\\\\\\\\/\\//\/\\/\///\//\\\//\\
/\/\\\\/\/\\/\\/\\/\\\\\\/\\\/\\//////\/\//\\\//\//\//\\/\\\/\//\\\//\\\\\\\/\/
\\\///\////////\\/////\\//\/\///\\\\\////\/\\\\/\//\\/\/////\\\//\\/\/\\\\\////
\///\/\/////\//\////\\\/\\/////\\\////\//\\\\/\\\\//\\\///\\\\\\//\\////\//////
/\/////\\\\\\//\\/\/\///\////\/\\\///\\///\//\/\/\\\/\\/\\\\\\//\/\\\///\\/\/\\
โฆ
\\/\//\\//\///\/\///\\\\/\//\/\\/\/\//\\/\/\/\\/\/\\/\\\\/\/////\\\///\\\\\//\\for y in range(10):
s=''
for x in range(25):
a=[]
for q in range(2):
z=c=x/25*3-2+1j*((y*2+q)/10-1);n=40
while n and abs(z)<2:z=z*z+c;n-=1
a+=[n<5]
s+=" โโโ"[a[0]+2*a[1]]
print(s)
โโ
โโโโโโโโ
โ โโโโโโโโโ
โโโโโโโโโโโโโ
โโโโโโโโโโโโโโโโโโโ
โโโ โโโโโโโโโ
โโโโโโโโ
โ โโโโ
โโ